Use your own types in geometric algebra expressions
Inputs
If the type you use supports indexing, e.g. Vector
, it already works:
using SymbolicGA
x = rand(3)
y = rand(3)
@ga 3 x::1 ∧ y::1
Bivector{Float64, 3, 3}(0.500258629818007, 0.5357843847349241, 0.0008175000041409294)
If your type does not support indexing, and you don't want it to, overload SymbolicGA.getcomponent(::T, [i::Int, [j::Int]])
:
struct MyInputType{T}
values::Vector{T}
end
SymbolicGA.getcomponent(x::MyInputType, i::Int) = x.values[i]
x = MyInputType(rand(3))
y = MyInputType(rand(3))
@ga 3 x::1 ∧ y::1
Bivector{Float64, 3, 3}(-0.2138652569661575, -0.20549721942467916, -0.3651673999054662)
For scalars and aggregates of objects with multiple grades, you will need to overload SymbolicGA.getcomponent(::T)
and SymbolicGA.getcomponent(::T, j::Int, i::Int)
respectively (see SymbolicGA.getcomponent
).
Outputs
If you want to reconstruct a custom type from components, either define a constructor for a single tuple argument, e.g. T(components::Tuple)
struct MyOutputType{T}
values::Vector{T}
end
MyOutputType(x::Tuple) = MyOutputType(collect(x))
x = rand(3)
y = rand(3)
@ga 3 MyOutputType dual(x::1 ∧ y::1)
Main.MyOutputType{Float64}([0.3266951213977226, -0.21724971388568257, -0.06799243644984554])
If you don't want such constructor to be defined, you can overload SymbolicGA.construct(::Type{T}, ::Tuple)
directly:
struct MyOutputType2{T}
values::Vector{T}
end
SymbolicGA.construct(T::Type{<:MyOutputType2}, x::Tuple) = MyOutputType2(collect(x))
x = rand(3)
y = rand(3)
@ga 3 MyOutputType2 dual(x::1 ∧ y::1)
Main.MyOutputType2{Float64}([0.14218485871355147, 0.11017877817638946, -0.3285963732843947])
Integrations for Vector
, Tuple
and <:Real
have already been defined:
@ga 3 Tuple dual(x::1 ∧ y::1)
(0.14218485871355147, 0.11017877817638946, -0.3285963732843947)
@ga 3 Vector dual(x::1 ∧ y::1)
3-element Vector{Float64}:
0.14218485871355147
0.11017877817638946
-0.3285963732843947
z = rand(3)
@ga 3 Float16 dual(x::1 ∧ y::1 ∧ z::1)
Float16(0.05515)
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