Use your own types in geometric algebra expressions

Inputs

If the type you use supports indexing, e.g. Vector, it already works:

using SymbolicGA

x = rand(3)
y = rand(3)

@ga 3 x::1 ∧ y::1
Bivector{Float64, 3, 3}(0.26469749987977, 0.0890482108730837, -0.4593467288220951)

If your type does not support indexing, and you don't want it to, overload SymbolicGA.getcomponent(::T, [i::Int, [j::Int]]):

struct MyInputType{T}
  values::Vector{T}
end

SymbolicGA.getcomponent(x::MyInputType, i::Int) = x.values[i]

x = MyInputType(rand(3))
y = MyInputType(rand(3))

@ga 3 x::1 ∧ y::1
Bivector{Float64, 3, 3}(0.09244282628243007, 0.11810953021924389, 0.05889841281861452)

For scalars and aggregates of objects with multiple grades, you will need to overload SymbolicGA.getcomponent(::T) and SymbolicGA.getcomponent(::T, j::Int, i::Int) respectively (see SymbolicGA.getcomponent).

Outputs

If you want to reconstruct a custom type from components, either define a constructor for a single tuple argument, e.g. T(components::Tuple)

struct MyOutputType{T}
  values::Vector{T}
end

MyOutputType(x::Tuple) = MyOutputType(collect(x))

x = rand(3)
y = rand(3)

@ga 3 MyOutputType dual(x::1 ∧ y::1)
Main.MyOutputType{Float64}([-0.11701381887481559, -0.0015584295138336077, 0.7178465870381671])

If you don't want such constructor to be defined, you can overload SymbolicGA.construct(::Type{T}, ::Tuple) directly:

struct MyOutputType2{T}
  values::Vector{T}
end

SymbolicGA.construct(T::Type{<:MyOutputType2}, x::Tuple) = MyOutputType2(collect(x))

x = rand(3)
y = rand(3)

@ga 3 MyOutputType2 dual(x::1 ∧ y::1)
Main.MyOutputType2{Float64}([-0.5125818151701541, 0.2531902465605811, 0.3805843467449878])

Integrations for Vector, Tuple and <:Real have already been defined:

@ga 3 Tuple dual(x::1 ∧ y::1)
(-0.5125818151701541, 0.2531902465605811, 0.3805843467449878)
@ga 3 Vector dual(x::1 ∧ y::1)
3-element Vector{Float64}:
 -0.5125818151701541
  0.2531902465605811
  0.3805843467449878
z = rand(3)
@ga 3 Float16 dual(x::1 ∧ y::1 ∧ z::1)
Float16(0.4924)

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